检讨书50字

C语言：输入一个2*3的整数矩阵和一个3*2的整数矩阵,使用指针数组实现这两个矩阵的相乘.程序如下：1.运行结构有错误2.输入第一个矩阵时为什么可以输入7个数据?#include main(){ int i,j,n,*tem[3];in 题一：#include void main() { int a=8,i=5,j=5,c=1,d=10,p,q; p=(i++)+(i++)+(i++); q=(++j)+(题一：#includevoid main(){int a=8,i=5,j=5,c=1,d=10,p,q;p=(i++)+(i++)+(i++);q=(++j)+(++j)+(++j);printf("%d,%d,%d,%d\n",p,q,i,j);}此代码在TC下编译,q #include main() { int x=1,y=3; x=9-(--y)-(--y); printf("%d",x); } #include main()#includemain(){ int x=1,y=3; x=y*4.8/2; printf("%d",x);}谁能帮我解释下这两个程序的运行过程? #include main( ) { int a[4][4]={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16}; int i,j,sum=_____#includemain( ){ int a[4][4]={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16};int i,j,sum=_____ ; for(i=0; i #include"stdio.h" main() { int a=1,b=2,c=3,t; while(a 30)有以下程序 #include main() { int b[3] [3]={0,1,2,0,1,2,0,1,2},i,j,t=1; for(i=0; i #include int b=2; int fun(int *k) {b=*k+b;return(b);} main() {int a[10]={1,2,3,4,5,6,7,8}, #include void main() {int aa[4][4]={1,2,3,4},{5,6,7,8},{3,9,10,2},#includevoid main(){int aa[4][4]={{1,2,3,4},{5,6,7,8},{3,9,10,2},{4,2,9,6}};int i,s=0;for(i=0;i #include "stdio.h" void fun(int a,int b) { int t; t=a,a=b,b=t; } main() { int c[10]={1,2,3,4,5,6,7#include "stdio.h"void fun(int a,int b){int t;t=a,a=b,b=t;}main(){int c[10]={1,2,3,4,5,6,7,8,9,0},i;for(i=0;i #include main ( ) { int a=10,y=0 ; do { a+=2 ; y+=a ; if (y>50) break ; } while (a=8) ; p#include main ( ){int a=10,y=0 ;do {a+=2 ;y+=a ;if (y>50)break ;}while (a=8) ;printf("a=%d y=%d\n",a,y) ;getch();}程序时如何运行的, #include main() { int i=1; while(!((i%2=#includemain(){int i=1; while(!((i%2==1)&&(i%3==2)&&(i%5==4)&&(i%6==5)&&(i%7==0)))++i; printf("\n >> The ladder has %d stages.\n",i); #include main() {int y,a; y=2,a=1; while(y--!=-1) {do{a*=y;a++;}while(y--);}printf(“%d,%d",a,y);} #includefor(inti=0;i main() {inti=560,h,m; h=i/60; m=i-60*h printf(“%d分钟?%d小时%d分钟”,i,h,m);} 结果为?求解? #include void main( ) { int x=1,y=0,a=0,b=0; switch(x) { case 1:switch(y) { case 0:a++;能不能帮我详细解释一下这个程序的运行过程及结果#include void main( ){ int x=1,y=0,a=0,b=0;switch(x){ case 1:switch(y){ case 0:a++; break;case #include void main() { int x=2,y; switch(x) { case 1:y=x ; break; case 2:y=-x ; case 3:y=x*3 ; break;case 4:y=4*x;printf(“%d\n”,y);} #include main() { int s=0,k; for(k=7;k>=0;k--) { switch(k) { case 1: case 4: case 7: s++; b#includemain(){ int s=0,k;for(k=7;k>=0;k--){ switch(k){ case 1:case 4:case 7: s++; break;case 2;case 3;case 6; break;case 0:case 5: s+=2; break;}}printf("s= 有以下程序#include main() { int c[6]={10,20,30,40,50,60},*p,*s; p=a; s=&c[5]; printf("%d\#includemain(){ int c[6]={10,20,30,40,50,60},*p,*s;p=a; s=&c[5];printf("%d\n",s-p);}为什么答案是5?不是50么? #include "stdio.h" #include "conio.h" struct n {int x,y;} d[2]={1,2,3,4}; main() {struct n *p=d; pr struct ord {int x,y;}dt[2]={1,2,3, #include int main(){ int x=0,y=0; while(x #include main() { struct node{int n;struct node *nest;} *p;#includemain(){struct node{int n;struct node *nest;} *p;struct node x[3]={{2,x+1},{4,x+2},{6,NULL}};p=x;printf("%d\n",p->n);printf("%d\n",p->next->n);} #include main() { int a=1,b=2,c=3,d=4,m=5,n=6; a=(m=a>b)&&(n=c>d)||++a==b--; printf("%d %d#includemain(){int a=1,b=2,c=3,d=4,m=5,n=6;a=(m=a>b)&&(n=c>d)||++a==b--;printf("%d %d %d %d\n",a,b,m,n);}为何是1 1 0 而不是0 1 0 a=(m=a>b)&&(n=c>d)||++a== #include main() { int a=1,b=2,c=3; c=(a+=a+2),(a=b,b+3); printf("%d,%d,%d\n",a,b,c); }这个程序的运行结果中,c的值为什么是4,不是5,求详细解释 #include void fun(int p) { int d=2; p=d++; printf(“%d”,p);} main() { int a=1; fun(a); printf(“%d #include int d=1; void fun (int p) { int d=5 ; d+=p++; printf( "%d " ,d ) ; }main (){ int a=3 ;fun(a);d+=a++;printf("%d\n" ,d );} #include void fun(int x) { if(x/2>0)fun(x/2); printf("%d",x); } main() { fun(3);printf("\n");}相关知识点：递归调用 #include void fun(int x) { x=20; } main() { int x=10; fun(x); printf("x=%d\n",x); }#includevoid fun(int x){x=20;}main(){int x=10;fun(x);printf("x=%d\n",x);} #include void fun(char c) {if(c>'x') fun(c-1); printf("%c",c); } main() {fun('z');} #include main() { int a=0; if(1) a=3; if(0) a=4; else a=5;printf("%d",a);}这语句怎么看不懂.if语句执行哪个?. #include void main( ) { int k=-3; if (k #include main(){int a=1,b=0; if(!a)b++; else if (a==0) if(a) b+=2; else b+=3; printf(b)