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对于不等式1/8（2t-t^2)≤x^2-3x+2≤3-t^2,试求对区间[0,2]上的任意x都成立的实数t的取值范围就是这个 高二数学已知不等式x²+px+q的解集为{x\1＜x＜2},则不等式x²+px+q\x²-5x-6＞0的解集是（） 当0≤x≤2时,不等式1/8（2t－t)≤x－3x+2≤3－t恒成立,求t的取值范围? 求是下列函数取得最大值、最小值的自变量的集合,并写出最大值、最小值各是多少.（1）y=2sinx,x∈R（2）y=2-cosx/3 ,x∈R 英语翻译Australia is called the Land Down Under (地球的另一边)because it is below the equator(赤道).It is one of the seven continents (大陆)of the world.It is also a country.　　The first people to live in Australia were aborigines.( 求使下列函数取得最大值,最小值的自变量x的集合,并分别写出最大值,最小值是什么.(1)y=1—1/2cosπ/3x,x∈R（2）y=3sin(2x+π/4),x∈R 英语翻译I will never forget the lessen which Mr.Li gave us.One day Mr.Li was speaking to us in our school meeting room.He began his speech by holding up a ￥100 bill.He asked,"Who would like this ￥100 bill?" Most of us put up our hands quickly 英语翻译Don't we allI was parked in front of the mall wiping off my car.I had just come from the car wash and was waiting for my wife to get out of work.Coming my way from across the parking lot was what society would consider a bum.From the look 3x平方+(-二分之三x+三分之一y平方)(2x-三分之二y)3x的平方+(-2分之3 x+3分之1 y的平方)(2x-3分之2y),其中x=-3分之1,y=3分之2,求值【（xy+2）（xy-2）-2x平方y平方+4】÷xy,其中x=10,y=-25分之1x（x+2y）-（x+1 求使下列函数取得最大最小值的自变量集合,并写出最大最小值.1.y-2sinx,x属于R 2.y=2-cos3/x,x属于R谢,求详解 写出最大值最小值的自变量集合,和写出最大值最小值各是多少 y=2sinx,x∈R,y=2-cosx/3,x∈R 第二题. 第五题 判断下列函数奇偶性:(1) f(x)=2x^4+3x^2 (2) f(x)=x^2-2X (3) f(x)=(x^2+1)/x (4) f(x)=x^2+1要详细的过程!谢谢!急! 判断函数f(x)=3x在R上的奇偶性 已知函数f(x)=2sin^2(π/4+x)-√3cos2x 1.求f(x)的最小正周期和单调减区间 已知函数F(X)=2sin²(π/4+X)-√3cos2x-1,x∈R,求f(X)的最小正周期 已知函数f(x)=2sin(x+π/4)^2-√3cos2x-1.x属于R.（1）求f(x)的最值和最小正周期（2）若h(x)=f(x+t)的图像关于点（-π/6,0)对称,且t属于（0,π）,求t的值（3）若x属于[π/4,π/2],总有If(x)-mI 函数f(x)=2sin^2(π/4+x)-根号3cos2x-1,(x属于R）的最小正周期 已知函数f(x)=2sin^2 (π/4 -x)-√3cos2x （1）求f(x)的最小正周期和单调递减区间 （2）若f(x) 九年级英语题(6)任务型阅读 Many children use the Internet to get useful knowledge and information, and to telax in their free time. __1__ Here are some rules to make sure you are asfe and have fun on the Internet. ●__2__ For example f(x)=3x-2 判断函数奇偶性 判断函数f（x）=sin（3x/4+3π/2）,x属于R的奇偶性,并求其单调递增区间 解方程2x²-3x-6=0用配方法,过程详细 找九年级上期末英语试题 满分120 时间90分钟 的试卷急用 各类题型都有 标明每题分数 2012九年级各地英语期末试卷 设定义域在[-2,2]上的偶函数f(x)在区间[0,2]上单调递减,若f(1-m) 人教版英语八年级和九年级的全册单元测试题与期中期末考卷还有七下的 若定义域在R上的函数f(x)=x^2-ax-x+6在区间(0,1)内单调递减,求实数a的取值范围 函数f(x)=llog3xl在区间【a,b]上的值域为【0,1】,则b-a的最小值为多少正确答案是2/3 急已知函数f(x)在定义域R上是偶函数,且在[0,+无穷）上为增函数,若f(a-2)-f(1-2a) 函数f(x)=ILOG3XI在区间[a,b]上的值域为【0,1】,则b-a的最小值为（ ）.