[(x+y)^2-(x-y)^2]÷(1/2xy)
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[(x+y)^2-(x-y)^2]÷(1/2xy)
[(x+y)^2-(x-y)^2]÷(1/2xy)
[(x+y)^2-(x-y)^2]÷(1/2xy)
前面是平方差
所以原式=(x+y+x-y)(x+y-x+y)÷(1/2xy)
=(2x)(2y)÷(1/2xy)
=4xy÷(1/2xy)
=4÷1/2
=8
=(x²+2xy+y²-x²+2xy-y²)÷(1/2xy)
=4xy÷(1/2 xy)
=8
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