sin^2cos^2化简
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sin^2cos^2化简
sin^2cos^2化简
sin^2cos^2化简
sin^2cos^2=(cos2a+1)/2*(1-cos2a)/2=1-cos2a^2/4=sin2a^2/4
sin^2acos^2a=1/4[sin2a]^2
sin^2cos^2=Cos[x]^2 - Cos[x]^4=1/8 (1-cos(4 x))
sin(2x)=2sinx*cosx
所以原式等于(sin(2x))2/4
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