x²-y²-3x-3y
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x²-y²-3x-3y
x²-y²-3x-3y
x²-y²-3x-3y
x²-y²-3x-3y
=(x-y)(x+y)-3(x+y)
=(x+y)(x-y-3)
问什么?
=(x+y)(x-y)-3(x+y)
=(x+y)(x-y-3)
x²-y²-3x-3y
x²-y²-3x-3y
x²-y²-3x-3y
x²-y²-3x-3y
=(x-y)(x+y)-3(x+y)
=(x+y)(x-y-3)
问什么?
=(x+y)(x-y)-3(x+y)
=(x+y)(x-y-3)