[2sin50°+sin10°(1+√3tan10°)]•√(sin²80°)
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/14 23:17:42
[2sin50°+sin10°(1+√3tan10°)]•√(sin²80°)
[2sin50°+sin10°(1+√3tan10°)]•√(sin²80°)
[2sin50°+sin10°(1+√3tan10°)]•√(sin²80°)
[2sin50°+sin10°(1+√3tan10°)]•√(2sin²80°)
= [2sin50 + sin10(cos10+√3sin10)/cos10]•√2sin80
= [2sin50cos10+2sin10(cos60cos10+sin60sin10)•√2sin80/cos10
= 2[sin50cos10 + sin10cos(60-10)]•√2
= 2sin(50+10)•√2
= √6
[2sin50°+sin10°(1+根号3tan10°)]乘sin10°等于?
化简[2sin50°+sin10°(1+√3tan10°)] √(2sin280°)
求值:[2sin50°+sin10°(1+√3tan10°)]×√2sin80°
[2sin50°+sin10°(1+√3tan10°)]•√(sin²80°)
求[2sin50°+sin10°(1+√3tan10°0]sin80°的值
sin10°sin50°为什么等于1/2(cos40-cos60)
2sin50 +sin10×(1+ √3tan10)
求值[2sin50°+sin10°(1+√3tan10°)]*√2(sin80°)*(sin80°)
求值:[2sin50°+sin10°(1+√3tan10°)]√(1-sin^2 10°)
化简:[2sin50°+sin10°*(1+√3 tan 10°)]√2sin^2 80°
[2sin50°+sin10°(1+√3tan10°)]*√2(sin80°)*(sin80度)
求[2sin50°+sin10°(1+√3(tan10°)]×√(2sin^280°)的值如图
化简[2sin50°+sin10°(1+√3tan10°)] √(sin²80°)尽量简单点
求值:【2sin50°+sin10°(1+根号3tan10°)】根号2sin280°
化简:[2sin50°+sin10°(1+根号3*tan10°)]*根号sin^280°
计算 sin10°^2 + sin50°^2 + sin10°sin50° 的值? 答案:3/4我没学和积化差 ,,请用别的方法!
2sin50°+2sin10°sin40°/cos10°
求(sin10°-根号3cos10°)/sin50°