#include #define MA(x) x*(x-1) void main() { int a=1,b=2; printf(“%d\n”,MA(1+a+b)); }请问诸位大侠,上面式子的结果为多少?

#include #define MA(x) x*(x-1) void main() { int a=1,b=2; printf(“%d\n”,MA(1+a+b)); }请问诸位大侠,上面式子的结果为多少?
#include #define MA(x) x*(x-1) void main() { int a=1,b=2; printf(“%d\n”,MA(1+a+b)); }
请问诸位大侠,上面式子的结果为多少?

#include #define MA(x) x*(x-1) void main() { int a=1,b=2; printf(“%d\n”,MA(1+a+b)); }请问诸位大侠,上面式子的结果为多少?
MA(1+a+b）=MA(4)=4*(4-1)=12