(2x-3/5y-1/3z)(3/5y-1/3y+2x)帮忙哈!

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(2x-3/5y-1/3z)(3/5y-1/3y+2x)帮忙哈!
(2x-3/5y-1/3z)(3/5y-1/3y+2x)帮忙哈!

(2x-3/5y-1/3z)(3/5y-1/3y+2x)帮忙哈!
[2x-(3/5)y-(1/3)z][(3/5)y-(1/3)z+2x]={[2x-(1/3)z]-(3/5)y}{[2x-(1/3)z]+(3/5)y}
=[2x-(1/3)z]²-(9/25)y²=4x²-(4/3)xz+(1/9)z²-(9/25)y²
=4x²-(9/25)y²+(1/9)z²-(4/3)xz.
[原题有错,已改正]

(2x-3/5y-1/3z)(3/5y-1/3y+2x)
~~~~这里应该是1/3z 吧?!
(2x-3/5y-1/3z)(3/5y-1/3z+2x)
=[(2x- 1/3z)- 3/5y]*[(2x- 1/3z)+ 3/5y]
=(2x- 1/3z)²- (3/5y)²
=4x²- 4/3*xz+ 1/9*z²- 9/25*y²

(2x-3/5y-1/3z)(3/5y-1/3y+2x)
=[(2x-1/3z)-3/5y][(2x-1/3z)+3/5y]
=(2x-1/3z)²-(3/5y)²
=4x²-4/3xz+1/9z²-9/25y²