x+2y=4,2x+3z=13 ,3y+z=6 这个三元一次方程的解x+2y=4 2x+3z=13 3y+z=6 过程,谢谢

x+2y=3x+2z=4y+z 求x:y:z x+y/2=z+x/3=y+z/4 x+y+z=27 试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) 已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z (4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=? -2X+3Y+Z=-4-X-5Y-2Z=-13X+Y-Z=10 5x+4y+z=0 3x+y-4z=13 x+y+z=—2 2x+3y+z=13 4x^2+9y^2+z^2-2x+15y+3z=82 求x,y,z (4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian 三元一次方程解 1.{x+y-z=5 {3x+2y+z=2 {2x-2y+z=-31.{x+y-z=5 2.{9x-5y+x=-6 3.{x-y=3 4.{x+y=3 5.{4x-2y+z=7{3x+2y+z=2 {9x+y-2z=3 {x+z=7 {y+z=4 {2x-y-3z=28{2x-2y+z=-3 {-9x+3y-5z=0 {y-z=6 {z+x=5 {x+y-2z=13 设|x|-|y|+|z|=|x+y+z|,且|x+y|=4,|y+z|=5,|y|=3,求(x-y-z)^2的值 2x+z=10 x+y-z=4 3x-y-z=0 x+y=5 2x+3y-z=9 x-y+z=4 {2x+y=10 {x-y+z=4 {3x-y-z=0 x=y/z=z/3,x+y+z ＝12,求2x+3y+4z是多少, 证明 ：x/(y+z)+y/(z+x)+z/(x+y)>=3/2其中 x,y,z>0 (4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊 x/2=y/3=z/5 x+3y-z/x-3y+z