（x-1)²/x²-(x-1)/x-2=0用换元法怎么计算?

（x-1)²/x²-(x-1)/x-2=0用换元法怎么计算?
（x-1)²/x²-(x-1)/x-2=0用换元法怎么计算?

（x-1)²/x²-(x-1)/x-2=0用换元法怎么计算?
令t=(x-1)/x
t²-t-2=0
(t-2)(t+1)=0
t=2或t=-1
(x-1)/x=2或(x-1)/x=-1
x-1=2x或x-1=-x
x=-1或x=1/2
经检验,x=-1或x=1/2都是原方程的根