作业帮若(x-3)/(x*x-1)=A/(x+1)-B/(x-1),求A.B的值
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若(x-3)/(x*x-1)=A/(x+1)-B/(x-1),求A.B的值
若(x-3)/(x*x-1)=A/(x+1)-B/(x-1),求A.B的值
若(x-3)/(x*x-1)=A/(x+1)-B/(x-1),求A.B的值
对等式右边通分,可得,A-B=1,A+B=3,所以可求的A=2,B=1 这就是过程呀!
对等式右边通分，可得，A-B=1,A+B=3,所以可求的A=2,B=1
(x-3)/(x*x-1)=A/(x+1)-B/(x-1)
(x-3)/(x+1)(x-1)=A(x-1)/(x+1)(x-1)-B(x+1)/(x+1)(x-1)
(x-3)/(x+1)(x-1)=(Ax-A-Bx-B)/(x+1)(x-1)
(x-3)/(x+1)(x-1)=[(A-B)x-(A+B)]/(x+1)(x-1)
对照等式两边，分母分子相等，得
A-B=1,A+B=3
A=2,B=1
进行通分后 可得A-B=1 A+B=3 A=2 B=1
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