先化简,再求值【2x/(x^2+x-12)】/【1-(x+3)/(x+4)】-【(x^2+5x)/(x^2+2x-15)】,其中x=42x x+3 x^2+5x----------------/ ( 1- ----------) - -----------x^+x-12 x+4 x^2+2x-15

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先化简,再求值【2x/(x^2+x-12)】/【1-(x+3)/(x+4)】-【(x^2+5x)/(x^2+2x-15)】,其中x=42x x+3 x^2+5x----------------/ ( 1- ----------) - -----------x^+x-12 x+4 x^2+2x-15
先化简,再求值【2x/(x^2+x-12)】/【1-(x+3)/(x+4)】-【(x^2+5x)/(x^2+2x-15)】,其中x=4
2x x+3 x^2+5x
----------------/ ( 1- ----------) - -----------
x^+x-12 x+4 x^2+2x-15

先化简,再求值【2x/(x^2+x-12)】/【1-(x+3)/(x+4)】-【(x^2+5x)/(x^2+2x-15)】,其中x=42x x+3 x^2+5x----------------/ ( 1- ----------) - -----------x^+x-12 x+4 x^2+2x-15
【2x/(x^2+x-12)】/【1-(x+3)/(x+4)】-【(x^2+5x)/(x^2+2x-15)】
=[2x/((x+4)(x-3))]/[((x+4)-(x-3))/(x+4)]-[x(x+5)]/[(x+5)(x-3)]
=[2x/((x+4)(x-3))] ×(x+4)-x/(x-3)
=2x/(x-3)-x/(x-3)
=x/(x-3)
 用word打一遍吧,

∵其中x=4
∴原式=4/(4-3)=4