关于matlab的varargin一段程序没看懂,function [xyinput_in,xybase_in,input,base] = ParseInputs(varargin)iptchecknargin(4,4,nargin,mfilename);%是在判断输入参数为4吗?xyinput_in = varargin{1};%varargin{1}什么意思啊?xybase_in = vara

关于matlab的varargin一段程序没看懂,function [xyinput_in,xybase_in,input,base] = ParseInputs(varargin)iptchecknargin(4,4,nargin,mfilename);%是在判断输入参数为4吗?xyinput_in = varargin{1};%varargin{1}什么意思啊?xybase_in = vara
关于matlab的varargin一段程序没看懂,
function [xyinput_in,xybase_in,input,base] = ParseInputs(varargin)
iptchecknargin(4,4,nargin,mfilename);
%是在判断输入参数为4吗?
xyinput_in = varargin{1};
%varargin{1}什么意思啊?
xybase_in = varargin{2};
if size(xyinput_in,2) = 2 || size(xybase_in,2) = 2
error(message('images:cpcorr:cpMatrixMustBeMby2'))
end
%size(xyinput_in,2) 是不是等于size(varargin{2},2) ,

关于matlab的varargin一段程序没看懂,function [xyinput_in,xybase_in,input,base] = ParseInputs(varargin)iptchecknargin(4,4,nargin,mfilename);%是在判断输入参数为4吗?xyinput_in = varargin{1};%varargin{1}什么意思啊?xybase_in = vara
function [xyinput_in,xybase_in,input,base] = ParseInputs(varargin)
iptchecknargin(4,4,nargin,mfilename);
%是在判断输入参数为4吗? 是!
xyinput_in = varargin{1};
%varargin{1}什么意思啊? 取4个参数中第一个参数赋给xyinput_in ,varargin是元胞
xybase_in = varargin{2};
if size(xyinput_in,2) ~= 2 || size(xybase_in,2) ~= 2
error(message('images:cpcorr:cpMatrixMustBeMby2'))
end
%size(xyinput_in,2) 是不是等于size(varargin{2},2) ,哪有具体是什么意思啊?
size(xyinput_in,2) 等于size(varargin{1},2),你看错了,另外size(a,2)指的是矩阵a的列数
希望对你有所帮助,有问题欢迎追问,满意请采纳.