若x²-y²=1且x>0,y>0,求x√(1+y²)-y√(x²-1)的值
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若x²-y²=1且x>0,y>0,求x√(1+y²)-y√(x²-1)的值
若x²-y²=1且x>0,y>0,求x√(1+y²)-y√(x²-1)的值
若x²-y²=1且x>0,y>0,求x√(1+y²)-y√(x²-1)的值
答案是1
若x²-y²=1且x>0,y>0,求x√(1+y²)-y√(x²-1)的值
若x²-y²=1且x>0,y>0,求x√(1+y²)-y√(x²-1)的值
若x²-y²=1且x>0,y>0,求x√(1+y²)-y√(x²-1)的值
答案是1