求值sin(9兀/4)+cos(2兀/3)+tan(5兀/4)

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求值sin(9兀/4)+cos(2兀/3)+tan(5兀/4)
求值sin(9兀/4)+cos(2兀/3)+tan(5兀/4)

求值sin(9兀/4)+cos(2兀/3)+tan(5兀/4)
sin(9兀/4)+cos(2兀/3)+tan(5兀/4)
=sin(2π+π/4)+cos(π-π/3)+tan(π+π/4)
=sinπ/4-cosπ/3+tanπ/4
=√2/2-1/2+1
=√2/2+1/2

=sinπ/4-1/2-1
=(根号2-3)/2

sin(9兀/4)+cos(2兀/3)+tan(5兀/4) =sin(兀/4)+cos(2兀/3)+tan(兀/4) =根号2/2-1/2+1=根号2/2+1/2

(根号2+1)/2

原式=sin(2兀+兀/4)+cos(兀-兀/3)+tan(兀+兀/4)=sin(兀/4)-cos(兀/3)+tan(兀/4)=√2/2-1/2+1=
√2/2+1/2