3^(1+log3 6) -2^(4+log2 3)+10^3lg3+(9/1)^log3^4题有个错误,+(9/1)^log3^4改为+(9/1)^log3^4-1
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3^(1+log3 6) -2^(4+log2 3)+10^3lg3+(9/1)^log3^4题有个错误,+(9/1)^log3^4改为+(9/1)^log3^4-1
3^(1+log3 6) -2^(4+log2 3)+10^3lg3+(9/1)^log3^4
题有个错误,+(9/1)^log3^4改为+(9/1)^log3^4-1
3^(1+log3 6) -2^(4+log2 3)+10^3lg3+(9/1)^log3^4题有个错误,+(9/1)^log3^4改为+(9/1)^log3^4-1
原式=3*3^log3(6)-(2^4)*2^log2(3)+(10^lg3)^3+(3^-2)^log3(4)
=3*6-16*3+3^3+[3^log3(4)]^(-2)
=18-48+27+4^(-2)
=-5+1/16
=-79/16
3^(1+log3 6) -2^(4+log2 3)+10^3lg3+(9/1)^log3^4题有个错误,+(9/1)^log3^4改为+(9/1)^log3^4-1
计算3^(1+log3 6) -2^(4+log2 3)+10^3lg3+(1/9)^log3^4-1
3^(1+log3 6)+10^(3lg 3)+1/9^(log3 4)RT
log2(6)*log3(6)-[log2(3)+log3(2)]的值
(log2 6)×(log3 6)-(log2 3+log3 2)=
log2(6)*log3(6)-[log2(3)+log3(2)]的值
(log2 6)×(log3 6)-(log2 3+log3 2)=
log3(9^x-4)=1+log3(3^x+2)解方程.
log3(x^2-3)=1+log3(x-5/3)
计算log3[(9^2 * 27^(1/3))/3^(log3 234)]
一道对数计算,log3(27/5)+log3(2/3)-log3(6/5)
已知log(32)9=p,log(27)25=q,适用p,q表示lg5p=log32(9)=2/5×log2(3)=2/5×1/log3(2)∴log3(2)=2/5pq=log27(25)=2/3×log3(5)∴log3(5)=3q/2lg5=log3(5)/log3(10)=log3(5)/[log3(2)+log3(5)]=15pq/(4+15pq)结果怎么出来的?
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