y=2cos(x/4+ π/3)-3sin(x- π/4)y=sin(4x- π/3)-cos(3x+π/2)
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y=2cos(x/4+ π/3)-3sin(x- π/4)y=sin(4x- π/3)-cos(3x+π/2)
y=2cos(x/4+ π/3)-3sin(x- π/4)
y=sin(4x- π/3)-cos(3x+π/2)
y=2cos(x/4+ π/3)-3sin(x- π/4)y=sin(4x- π/3)-cos(3x+π/2)
这类的最小正周期(就是说正、余弦的和差,且x的系数不同的,也不能利用公式计算的)
就是求两个最小正周期的最小公倍数.
如1中,两个最小正周期分别为8π和2π,所以函数的最小正周期为8π;
2中,两个最小正周期分别为π/2和2π/3
分数1/2和2/3的最小公倍数为分子的最小公倍数2除以分线的最大公约数1,所以函数的最小正周期仍为2π
设f(x)=4cos(ωx-π/6)sinωx-cos(2ωx+π),其中ω>0,求函数y=f(x)的值域,请看问题补充f(x)=4cos(ωx-π/6)sinωx-cos(2ωx+π) =4(coswxcosπ/6+sinwxsinπ6)sinwx+cos2wx =2√3sinwxcoswx+2sin²wx+cos2wx =√3si
y=3cos(2x+π/4) (2)y=2cos(x-π/6)的单调区间
若cos(x+y)=4/5,cos(x-y)=-4/5,且3π/2
y=cos(π/3-x)cos[π/2(x-1)]判断奇偶性y=cos(π/3-x)cos(π/3+x)判断奇偶性
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函数y=cos(3π/2-x)/cos(3π-x)最小正周期是
函数y=cos(3π/2-x)/cos(3π-x)最小正周期是:
y=4cos(x/3),0
化简y=(2cos^4x-3cos^2x+1)/cos2x
y=2cos(x/4+ π/3)-3sin(x- π/4)y=sin(4x- π/3)-cos(3x+π/2)
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函数y=3cos(2x-π/3)最小值
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Y=cos(3x-π/4)的导数
y=2cos(2x-π/3)的值域