1/2x1/n+1x1/n+2怎么等于1/2(1/n+1-1/n+2)

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1/2x1/n+1x1/n+2怎么等于1/2(1/n+1-1/n+2)
1/2x1/n+1x1/n+2怎么等于1/2(1/n+1-1/n+2)

1/2x1/n+1x1/n+2怎么等于1/2(1/n+1-1/n+2)
1/2x1/(n+1)x1/(n+2)
=1/2x1/((n+1)(n+2))
[由1=(n+2)-(n+1)]
=1/2x((n+2)-(n+1))/((n+1)(n+2))
乘法分配
=1/2x[(n+2)/((n+1)(n+2))-(n+1)/((n+1)(n+2))]
分子分母约去
=1/2x[1/(n+1)-1/(n+2)]
还有,梓萌是什么情况

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