求证:sin^2A+sin^2B-sin^2Asin^2B+cos^2Acos^2B=1

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/29 00:50:54

求证:sin^2A+sin^2B-sin^2Asin^2B+cos^2Acos^2B=1
求证:sin^2A+sin^2B-sin^2Asin^2B+cos^2Acos^2B=1

求证:sin^2A+sin^2B-sin^2Asin^2B+cos^2Acos^2B=1
左式=sin²A(1-sin²B)+sin²B+(1-sin²A)cos²B=sin²Acos²B+sin²B+cos²B-sin²Acos²B=sin²B+cos²B=1
右式=1
左式=右式
证毕