y=sin(2x+π/6),x∈[π/4,3π/4]求值域

判断单调性 y=sin(x-π/6) y=sin(-2x+π/3) y=sin(2x+π/6),x∈[π/4,3π/4]求值域 y=sin(x+π/6)+sin(x-π/6)+cosx ,x∈[-π/2,π/2]的值域 y=2sin三分之一x y=4sin(x-π/3) y=sin(2x+π/6) y=3sin(1/2x-π/4) 的周期各是多少, 求下列函数周期 y=3sin(x/4) x属于Ry=2sin(2x-π/6) 已知sinx=3/5,x∈(π/2,π),求【sin(x+y)+sin(x-y)】/【cos（x+y）+cos（x-y）】的值 5cos（2x-y）+7cosy=0 ,tan（x-y）tanx=?y=sin²（x+π/4)-sin²（x-π/4),x∈（π/6,π/3）值域 函数y=4sin(x+π/6)+3sin(π/3-x)的最大值是多少 y=12sin(2x+π/6)+5sin(π/3-2x)最大值 y=12sin(2x+π/6)+5sin(π/3-2x)的最大值 函数y=2sin(π/3-X)+sin(π/6+X)的最大值 求函数的值域y=sin(2x+π/3),x∈(-π/6,π) 函数y=sin^2x+2/sinx,x∈[π/6,2π]的最小值 y=2sin(2x+π/6）x∈[0,π/2],求值域 y=sin(π/6-3x),x∈[0,π/4]的单调区间. 函数y=2sin(x+π/6),x∈【0,π/2】,值域是 y=sin(2x+π/6),x属于[π/6,3π/4],求值域 求y=sin(2x+π/6)x∈(0,π/3)的值域