作业帮99...9(1998个9)*99...9(1998个9)+199...9(1998个9)=?
来源：学生作业帮助网 编辑：作业帮 时间：2024/04/30 03:41:06
99...9(1998个9)*99...9(1998个9)+199...9(1998个9)=?
99...9(1998个9)*99...9(1998个9)+199...9(1998个9)=?
99...9(1998个9)*99...9(1998个9)+199...9(1998个9)=?
=(10^1998 - 1) * (10^1998 - 1) + 2*10^1998 - 1
= 10^3996 - 2*19^1998 +1 + 2*19^1998 - 1
= 10^3996
99...9(1998个9)*99...9(1998个9)+199...9(1998个9)
=99...9(1998个9)*99...9(1998个9)+[99...9(1998个9)+100...0(1998个0)]
=99...9(1998个9)*[99...9(1998个9)+1]+100...0(1998个0)
=99...9(1998个9)*100...0(199...
全部展开
99...9(1998个9)*99...9(1998个9)+199...9(1998个9)
=99...9(1998个9)*99...9(1998个9)+[99...9(1998个9)+100...0(1998个0)]
=99...9(1998个9)*[99...9(1998个9)+1]+100...0(1998个0)
=99...9(1998个9)*100...0(1998个0)+100...0(1998个0)
=[99...9(1998个9)+1]*100...0(1998个0)
=100...0(1998个0)*100...0(1998个0)
=100...0(3996个0)
收起
99...9*99...9+199...9 1998个9 1998个9 1998个9
99...9(1998个9)*99...9(1998个9)+199...9(1998个9)=?
99...9(2003个9)*99...9(2003个9)+199...9(2003个9)是多少?
计算 11.1(n个1)*99...9(n个9)
99.9【100个9】×99.【100个9】+99.【100个9】+100.0【100个0】简便运算
99...9【2000个9】x99...9【2000个9】+199...9【2000个9】
99...9(2000个9）×99...9（2000个9）+199...9（2000个9）
99...9(100个9)*99...9(100个9)+199...9(100个9)末尾有几个零
99...9（n个9）×99...90（n个9）＋199...9（n个9）
求证:8 99...9(n-1)个 4 00...0(n-1个)个 1是完全平方数
999...9(1992个9）*99...9(1992个9）+199...9(1992个9）的末尾有多少个零
11...1×99...9(10个1,10个9)最前面9个1,最后一位9,共10个奇数.你选错答案了.
99...98(1997个9）×99.98(1997个9）+1998...98*2(1997个9）末尾有多少个零
根号(99...9)^2+199...9 2013个9 2013个9
9+99+999+...+99...9[2002个9】的和中共有多少个数字1?
999...99(2006个9）乘99...97(2005个9）
2010个66...6乘2010个99...9等于多少
(1+3+5...+1999+2001)-(2+4+6...+1998+2000+2002)求出最后等于多少99...9 * 99...9 +199...9中间省略的部分都是有2000个9,第二个是,2000个9乘以2000个9加上1999999999.（这里也是2000个9）