2y+8y-1=0
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2y+8y-1=0
2y+8y-1=0
2y+8y-1=0
2y+8y-1=2(y+4y+4)-1-8=2(y+2)-9=0 所以(y+2)=2/9 即y+2=√2/3或者-√2/3 所以y=√2/3-2或者y=-√2/3-2
y-2[y-4(y-1)]-8=0
2y+8y-1=0
[T,Y]=ode45(@rigid,[0 1],[rand(15,1)]);plot(T,Y(:,1),'-',T,Y(:,2),'-.',T,Y(:,3),'.',T,Y(:,4),'-',T,Y(:,5),'-.',T,Y(:,6),'.',T,Y(:,7),'-',T,Y(:,8),'-.',T,Y(:,9),'.',T,Y(:,10),'-',T,Y(:,11),'-.',T,Y(:,12),'-.',T,Y(:,13),'.',T,Y(:,14),'-',T,Y(:,15),'.')
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y (3y^2+8y-3)-6y(3y+2y-1)+9y
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y- 2y+1/2=9- 8-y/4
y-2y+1/2=9-8-y/4
y+2*y'^2/(1-y)=0的通解
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2y''+y'-y=0
提问A={y/y^2-(a^2+a+1)y+a(a^2+1)>0} B={Y/Y^2-6y+8
已知集合A={y|y^2-(a^2+a+1)y+a(a^2+1)>0},B={y|y^2-6y+8