化简[cos(a-π)/sin(π-a)]sin(a-π/2)cos(π/2+a)=化简[cos(2π-a)sin(π+a)]/[sin(π/2+a)tan(3π-a)]=

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化简[cos(a-π)/sin(π-a)]sin(a-π/2)cos(π/2+a)=化简[cos(2π-a)sin(π+a)]/[sin(π/2+a)tan(3π-a)]=
化简[cos(a-π)/sin(π-a)]sin(a-π/2)cos(π/2+a)=
化简[cos(2π-a)sin(π+a)]/[sin(π/2+a)tan(3π-a)]=

化简[cos(a-π)/sin(π-a)]sin(a-π/2)cos(π/2+a)=化简[cos(2π-a)sin(π+a)]/[sin(π/2+a)tan(3π-a)]=
[cos(a-π)/sin(π-a)]sin(a-π/2)cos(π/2+a)
=[-cosa/sina](-cosa)(-sina)
=-cos^2a